Math, asked by ashujaguar533, 9 months ago

Simplify. Cos theta/Sin (90° -theta)+Cos(90°-theta)/sec(90°-theta)-3tan²30°

Answers

Answered by santoshamelia
6

Answer:

sin²Θ

Step-by-step explanation:

cosΘ/sin(90-Θ)+Cos(90-Θ)/Sec(90-Θ)-3tan²30

=cosΘ/cosΘ+SinΘ/cosecΘ-3*(1/√3)²

=1+sinΘ/1/sinΘ-3*1/3

=1+sin²Θ-1

=sin²Θ

Answered by sandy1816
4

Answer:

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