Math, asked by aayushav12, 1 month ago

Simplify d) [ -a^-5 / -a^10 b^-9 c^-7 × (a^-15 × c^0 ] ^2​

Answers

Answered by sabbisettyvijay3
0

Answer:

1/(-a^-15 b^-9 c^-7)

Step-by-step explanation:

-a^-5/(-a^10 b^-9 c^-7)*(a^-15*1)^2. { c^0=1 }

-a^-5/(-a^10 b^-9 c^-7)*(a^-30). {(a^m)^n= a^a(m*n)}

-a^-5/(-a^10*a^-30* b^-9 c^-7). (a^m*a^n= a^m+n)

-a^-5/(-a^-20*b^-9 c^-7)

1/(-a^-15*b^-9*c^-7)

Similar questions