Question

simplify each of the following by rationalising the denominator of 3✓5-✓7/3✓3+✓2​

Answer 1

Step-by-step explanation:

Given (3√5-√7)/(3√3 + √2)

=[(3√5-√7)(3√3-√2)]/[(3√3+√2)(3√3-√2)]

=[9√15-3√10-3√21+√14]/[(3√3)²-(√2)²]

[ Since x²-y² =(x+y)(x-y)]

=[9√15-3√10-3√21+√14]/(27-2)

= (9√15-3√10-3√21+√14)/25

Answer 2

Answer:

Step-by-step explanation:

The rationalising factor of 3√3+√2 is 3√3-√2

Now ,

3√5-√7 / 3√+√2 × 3√3-√2 / 3√3-√2

= 3√5 [3√3-√2] - √7 [3√3-√2] / (3√3)²-(√2)²

= 9√15-3√10-3√21+√14 / 9×3-2

= 9√15-3√10-3√21+√14 / 27-2

= 9√15-3√10-3√21+√14 / 25

★Completed★