Question

Simplify each of the following products:
2 2
(i)
25 5 5 2
х
X
x² + 2x
(if​

Answer 1

Let (x−a) be the other factor.

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2 −ax+5x−5a=x

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2 −ax+5x−5a=x 2

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2 −ax+5x−5a=x 2 +x−20

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2 −ax+5x−5a=x 2 +x−20=>x(5−a)−5a=x−20

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2 −ax+5x−5a=x 2 +x−20=>x(5−a)−5a=x−20Now, considering the co-efficients of x on the both sides,

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2 −ax+5x−5a=x 2 +x−20=>x(5−a)−5a=x−20Now, considering the co-efficients of x on the both sides,5−a=1

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2 −ax+5x−5a=x 2 +x−20=>x(5−a)−5a=x−20Now, considering the co-efficients of x on the both sides,5−a=1=>a=5−1=4

Let (x−a) be the other factor.Now, (x+5),(x−a) are factors of the quadratic equation x 2 +x−20Thus,(x+5)(x−a)=x 2 +x−20=>x 2 −ax+5x−5a=x 2 +x−20=>x(5−a)−5a=x−20Now, considering the co-efficients of x on the both sides,5−a=1=>a=5−1=4Therefore the other factor is (x−4)