Math, asked by zareenrozy336, 12 days ago

SIMPLIFY (EXPONENTS)
(2n + 1); (2); a^ m3 * alpha (a^ 3 )^ 2n+1 .a^ mL 2n+15​

Answers

Answered by angelsaini20011
1

Answer:

(i) a2n -3. a(2n+1)(n+2)/(a3)2n+1. an(2n+1)

(ii) x2n+7. (x2)3n+2/x4(2n+3)

Given expression = x2n+7 . x6n+4/x8n+12

= x2n+7 + 6n+4/x8n+12 = x8n + (+11)/x8n+12

= x8n + 11 – 8n -12 = x-1

= 1/x

Answered by gautamrajr2
1

Answer 29-Apr-2019 — (i) a2n -3. a(2n+1)(n+2)/(a3)2n+1. an(2n+1). (ii) x2n+7. (x2)3n+2/x4(2n+3). Given expression = x2n+7 . x6n+4/x8n+12. = x2n+7 + 6n+4/x8n+12 ...

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