Question

simplify (exponents)
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Answer 1

Answer:

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Answer 2

$\frac{2^{n+1} *4^{n+1} }{2^{n-1}*4^{n-1}}\\\\ \frac{2^{n+1}*2^{2(n+1)}}{2^{n-1}*2^{2(n-1)}}\\\\\frac{2^{n+1}*2^{2n+2}}{2^{n-1}*2^{2n-2} }\\\\rule\\x^{a}*x^{b} = x^{a+b} \\so,\\\\\frac{2^{n+1+2n+2}}{2^{n-1+2n-2} }\\\\\frac{2^{3n+3}}{2^{3n-3} } \\\\rule\\\frac{x^{a} }{x^{b} }= x^{a-b}\\\\so,\\\frac{2^{3n+3}}{2^{3n-3}}\\\\2^{3n+3-(3n-3)} \\\\2^{3n+3-3n+3}\\\\2^{6}\\\\=64$