Math, asked by Harpreetdhanju9471, 11 months ago

Simplify exponents =(a^0b^-2)^5/2a^-1

Answers

Answered by LamhaMehrotra
4

Answer:a/2b^10

Step-by-step explanation:

(1*b^-2)^5/2*1/a

= 1*b^10/2/a

=b^10/2/a

=(1/b^10)/(2/a)

=1/b^10*a/2

=a/2b^10 is your answer.

Answered by amitnrw
4

Given  :  (a^0b^-2)^5/2a^-1    ( (a⁰b⁻²)⁵ / 2a⁻¹)

To Find :   Simplify

Solution:

(a^0b^-2)^5/2a^-1

(a⁰b⁻²)⁵ / 2a⁻¹

(aⁿ)ˣ = aⁿˣ

a⁻ⁿ = 1/aⁿ   or aⁿ = 1/a⁻ⁿ

x⁰ = 1    if x ≠ 0

= (a⁰b⁻²)⁵ / 2a⁻¹

a⁰  = 1

= (1 * b⁻²)⁵ / 2a⁻¹

= ( b⁻²)⁵ / 2a⁻¹

= b⁻¹⁰ /2a⁻¹

= 1/2a⁻¹ . b¹⁰

= a/2b¹⁰

(a⁰b⁻²)⁵ / 2a⁻¹ = a/2b¹⁰

Learn More:

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