Math, asked by raven05, 1 year ago

simplify fast............​

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Answers

Answered by SiddheshAkolkhedkar
0

Answer:

we can solve this by this identity

(a-b-c)^2=(a)^2+(-b)^2+(-c)^2+2ab+2bc+2ca

Step-by-step explanation:

 ({ a})^{2} + ( { \frac{ -b}{2} })^{2}  +  ({ \frac{ - c}{3} })^{2}   +  2 \times a \times  \frac{ - b}{2}  + 2 \times   -  \frac{b}{2}  \times  -  \frac{c}{3}  + 2 \times  -  \frac{c}{3}  \times a \\   {(a -  \frac{b}{2}  -  \frac{c}{3})}^{2}

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