Math, asked by shankar2045, 1 month ago

simplify giving answers with positive index​

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Answered by llMissDramaQueenll
0

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Answered by Anonymous
22

\Large{\underline{\underline{\huge{\bold{Question \: :-}}}}}

 \Large\sf\frac{(7 {p}^{2}  {q}^{9}  {r}^{5})^{2} (4pqr)^{3}  }{ (14 {p}^{6}  {q}^{10}  {r}^{4)^{2} } }

\Large{\underline{\underline{\huge{\bold{Solution \: :-}}}}}

~First we multiply the value of the exponent which is outside the bracket to the exponents of the digits inside the bracket

\Large\sf \:  =  \frac{7 {p}^{4}  {q}^{18}  {r}^{10}  \times  {4}^{3}  {p}^{3}  {r}^{3} }{ {14}^{2} {p}^{12}  {r}^{8}  }

~Now we write the constants and the variables separately

\Large\sf \:  =   \frac{ {7}^{2}  \times  {4}^{3} }{ {14}^{2} }  \times  \frac{ {p}^{4 + 3} {q}^{18 \times 3}  {r}^{10 + 3}  }{ {p}^{12} {r}^{8}  }

~In the next step, we'll multiply and solve

\Large\sf \:  \frac{7 \times 7 \times 4  \times 4 \times 4}{14 \times 14}  \times   \frac{ {p}^{7}  \ {q}^{21} {r}^{13}   }{ {p}^{12}  {q}^{20} {r}^{8}  }

(To make the equation simpler, we'll write the "14×14" as (7×2)² = 7×7×2×2)

\Large\sf \:  \frac{7 \times 7 \times 4  \times 4 \times 4}{7 \times 7 \times2 \times 2}  \times   \frac{ {p}^{7}  \ {q}^{21} {r}^{13}   }{ {p}^{12}  {q}^{20} {r}^{8}  }

~Now Cancel and solve!!

 \large\sf\:  = 4 \times 4 \:  {p}^{7 - 12}  \:  {q}^{21 - 20}  \:  {r}^{13 - 8}

\Large\sf \underline\color{purple}{16 \:  {p}^{ - 5}  \: {q}^{1}  \:  {r}^{5}  }

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