Simplify :
[i] (1^3+2^3+3^3)^1÷2
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Answered by
1
Is your answer my friend
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Answered by
1
Answer:
→ 6.
Step-by-step explanation:
Solution:
Given,
(1^3 + 2^3 + 3^3)^1/2
=> (1*1*1 + 2*2*2 + 3*3*3)^1/2
=> (1 + 8 + 27)^1/2
=> (9 + 27)^1/2
=> (36)^1/2
=> (6^2)^1/2
=> 6^2*1/2
★ In power both 2 will be cancel out.
=> 6^1
=> 6 Ans.
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