Math, asked by dubeynikhil2005, 1 year ago

Simplify :
[i] (1^3+2^3+3^3)^1÷2

Answers

Answered by AbhishekKumargope
1

Is your answer my friend

Attachments:
Answered by Salmonpanna2022
1

Answer:

→ 6.

Step-by-step explanation:

Solution:

Given,

(1^3 + 2^3 + 3^3)^1/2

=> (1*1*1 + 2*2*2 + 3*3*3)^1/2

=> (1 + 8 + 27)^1/2

=> (9 + 27)^1/2

=> (36)^1/2

=> (6^2)^1/2

=> 6^2*1/2

★ In power both 2 will be cancel out.

=> 6^1

=> 6 Ans.

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