Question

simplify i+i²+i³.......i⁴⁰​

Answer 1

We know, iota (i) is the square root of -1

Therefore,

i=√-1

i²= -1

i³= √-1

i⁴= 1

Therefore,

i+i²+i³+i⁴=0

Since 40 is a multiple of 4,

Therefore,

The answer should be 0

Hope you will understand...Thank You....

Answer 2

Step-by-step explanation:

I hope it helps you. If you have any doubts, then don't hesitate to ask.