Question

Simplify:
iii)49×z^-3/7^-3×10×z^-5.
(z is not equal to 0)

Answer 1

Answer:

$\frac{16807.z^{2}}{10}$.

Step-by-step explanation:

In the given question,

We have been provided the given equation that is needed to be simplified,

$\frac{49z^{-3}}{7^{-3}\times 10\times z^{-5}}$

For the simplification of the problem.

On simplifying the term we get,

$\frac{49z^{-3}}{7^{-3}\times 10\times z^{-5}}=\frac{7^{2}.z^{-3}}{7^{-3}\times 10\times z^{-5}}\\=\frac{7^{5}.z^{5-3}}{10}$

We know that from the equations,

$\frac{a^{m}}{a^{n}}=a^{m-n}\\and,\\a^{m}\times a^{n}=a^{m+n}$

Therefore,

Using the same properties, we can say that,

$\frac{7^{5}.z^{5-3}}{10}=\frac{7^{5}.z^{2}}{10}\\=\frac{16807.z^{2}}{10}\\=(1680.7)z^{2}$

Therefore, the final simplified form of the given equation is given by,

$\frac{16807.z^{2}}{10}$

Hence, the correct answer is $\frac{16807.z^{2}}{10}$.

Answer 2

Answer:

Ur ans plz mark brainlist