simplify it log2+16log(16/15) +12log(25/23) +7log(81/80)
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Change everything to log 2, log 3, and log 5. log 2 = log 2 16 log (16/15) ... How can I solve for x if log base 9 of x + log base 3 of x = 6? ... LHS = 7 log(10/9) - 2log(25/24) + 3 log( 81/80)
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