Question

Simplify it no spam

Answer 1

Answer:

$\frac{ {4}^{3x - 1} \times {16}^{2x - 1} }{ {32}^{3x - 1} } \\ = \frac{ {( {2}^{2} )}^{3x - 1} \times {( {2}^{4} )}^{2x - 1} }{ {( {2}^{5} )}^{3x - 1} } \\ = \frac{ {2}^{6x - 2} \times {2}^{8x - 4} }{ {2}^{15x - 5} } \\ = \frac{ {2}^{6x - 2 + 8x - 4} }{ {2}^{15x - 5} } \\ = \frac{ {2}^{14x - 6 } }{ {2}^{15x - 5} } \\ = {2}^{14x - 6 - (15x - 5)} \\ = {2}^{14x - 6 - 15x + 5} \\ = {2}^{ - x - 1} \\ = {2}^{ - (x + 1)} \\ = \frac{1}{ {2}^{ (x + 1)}}$