Question

Simplify it:
please help me in understanding how to find the answer of:
$(\frac{1}{9}) ^{ - 2} - 3 \times {27}^{ \frac{2}{3} } \times {9}^{0} + \frac{9}{81}^ {\frac{ - 1}{2} }$
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Answer 1

Answer:

you answer is 243+3√2/3

hope this will help. you

Answer 2

Answer:

57

Step-by-step explanation:

$= ( \frac{1}{9} )^{ - 2} - 3 \times {27}^{ \frac{2}{3} } \times {9}^{0} + ( \frac{9}{81}^{ \frac{ - 1}{2} }$

$= {9}^{2} - 3 \times ( \sqrt[3] {27})^{2} \times {9}^{0} + ( \frac{81}{9} )^{ \frac{ 1}{2} }$

$= 81 - 3 \times 9 \times 1 + \frac{9}{3}$

$= 81 - 27 + 3$

$81 - 24$

$= 57$