Question

Simplify it: Plzzzz​

Answer 1

by opening the both determinant we have

sinA ( sin²A + cos²A ) + cosA (cos²A + sin²A)

we know that sin²A + cos²A = 1

therefore

we have sinA + cosA

which is the required answer

Answer 2

Answer:

Step-by-step explanation:

i hope you can see attachment