Question

Simplify log2 x + log4 x + log16 x=2​

Answer 1

Answer:

$x = \sqrt[3]{100 \div 128}$

Step-by-step explanation:

log 2x + log 4x + log 16x = 2

log (2x*4x*16x) =2

log (128 x^3) = 2

taking antilog on both side

antilog of 2 is 100

128 x^3 = 100

x^3 = 100/128

x= {100/128}^(-1/3)