Math, asked by chhemanthkumar2345, 5 months ago

simplify log5+3log2-log10​

Answers

Answered by jaya1012
2

Hiii....friend,

Here is ur answer,

 =  >  log(5)  + 3 log(2)  -  log(10)

 =  >  log(5)  + 3 log(2)  -  log(5 \times 2)

 =  >  log(5)  + 3 log(2)  -  log(5)  -  log(2)

 =  > 2 log(2)

 =  > 2 \times 0.3010

 =  > 0.6020

:-) Hope it helps u.

Answered by payalchatterje
0

Answer:

Required answer is 2 log(2)

Step-by-step explanation:

Given,

 log(5)  + 3 log(2)  -  log(10)

 =  log(5)  +  log( {2}^{3} )  -  log(10)  \\  =  log(5)  +  log(8)  -  log(10)

We know,

 log(x)  +  log(y)  =  log(xy)

Now,

 =  log(5 \times 8)  -  log(10)  \\  =  log(40)  -  log(10)

Again,

 log(x)  -  log(y)  =  log( \frac{x}{y} )

So,

 log(40)  -  log(10)   \\ =  log( \frac{40}{10} )  \\  =  log(4)  \\  =  log( {2}^{2} )  \\  = 2 log(2)

This is a problem of Logarithm.

Some important Logarithm formulas,

log_{x}(1)  = 0 \\ log_{x}(0)  = 1 \\ log_{x}(y)  =  \frac{ log(x) }{ log(y) }  \\ log( {x}^{y} )  = y log(x)  \\ log(x)  +  log(y)  =  log(xy)  \\ log(x)  -  log(y)  =  log( \frac{x}{y} ) \\  log_{x}(x)  = 1

Know more about Logarithm, https://brainly.in/question/21862262

https://brainly.in/question/4881267

#SPJ2

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