Question

simplify (m-2n+3c)2-(m+2n-3c)2​

Answer 1

• Answer :-

→ (m - 2n + 3c)² - (m + 2n - 3c)²

• a² - b² = (a + b)(a - b)

→ [(m - 2n + 3c) + (m + 2n - 3c)][(m - 2n + 3c) - (m + 2n - 3c)]

→ [m - 2n + 3c + m + 2n - 3c][m - 2n + 3c - m - 2n + 3c]

→ [m + m - 2n + 2n + 3c - 3c][m - m - 2n - 2n + 3c + 3c]

→ 2m(-4n + 6c)

→ - 8mn + 12mc

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Answer 2

$( {m - 2n + 3c})^{2} - ({m + 2n - 3c})^{2} \\ we \: know \\ {a}^{2} - {b}^{2} = (a + b)(a - b) \\ here \\ a = m - 2n + 3c \\ b = m + 2n - 3c$

$so \\ ((m - 2n + 3c) + (m + 2n - 3c)) \\ ((m - 2n + 3c) - (m + 2n - 3c)) \\ =(m - 2n + 3c + m + 2n - 3c) \\ (m - 2n + 3c - m - 2n + 3c) \\ = (2m)( - 4n + 6c) \\ = - 8mn + 12mc$

Steps to do this question

• observe question properly
• use suitable identity to solve this question
• now this question become full calculation based you have not to distract when you do this question
• you have to make this question small as you can
• small means 2-3constant with one variable
• here we have mn and mc with-8 and 12