Question

simplify (m+n)(m square-mn+n square)

Answer 1

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Answer 2

The vaue of $(m+n)(m^2-mn+n^2)$ is $m^{3}+n^{3}.$

Step-by-step explanation:

Given by questions,

$(m+n)(m^2-mn+n^2)$

To find, the value of $(m+n)(m^2-mn+n^2)=?$

∴ $(m+n)(m^2-mn+n^2)$

$=m(m^2-mn+n^2)+n(m^2-mn+n^2)$

$=(m^{3}-m^{2}n+n^{2}m)+(nm^2-n^{2}m+n^{3})$

$=m^{3}-m^{2}n+n^{2}m+nm^2-n^{2}m+n^{3}$

$=m^{3}+n^{3}$

Hence, the vaue of $(m+n)(m^2-mn+n^2)$ is $m^{3}+n^{3}.$