Math, asked by monishka97, 1 month ago

SIMPLIFY. MY ANSWER PLEASE, PLEASE ​

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Answered by jhumap2015
5

Answer:

WE KNOW THAT, IN BODMAS

B - BAR

O - OF

D - DIVIDE

M - MULTIPLICATION

A - ADDITION

S - SUBTRACTION

1. 5{(-6)+(12÷4)}

= 5{(-6)+3}

= 5×(-3)

= (-15)

2. 10- {56÷(-16+9)}

= 10- {56÷(-7)}

= 10-(-8)

= 10 + 8

= 18

3.(-6)- {(-28)÷(-7)}

=(-6)- 4

= (-10)

4. 8- {12-(9- bar 】7-4)}

= 8 - {12-(9-3)}

= 8 - {12-6}

= 8 - 6

= 2

5. 11-[(-8)-{10-(9-【bar】7-4}]

= 11- [ (-8)- { 10-( 9-3)}]

= 11- [ (-8) - { 10 - 6}]

= 11- [ (-8) - 4]

= 11- ( - 12)

= 11 + 12

= 23

6. (-9)-[(-5) - {11-(8- 【bar】5-2)}]

= (-9) -[(-5) - {11-(8-3)}]

= (-9) - [(-5)- { 11-5}]

= (-9) - [(-5)-6]

= (-9) - (-11)

= (-9) + 11

= 2

7. 10-[8- {11+30÷(4 - 【bar】5-7)}]

= 10-[8- { 11+30÷(4-((-2))}]

= 10-[8- { 11+30÷(4+2)}]

= 10-[8- { 11+30÷6}]

= 10-[8- {11+5}]

= 10-[8-16]

= 10-(-8)

= 10+8

= 18

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