Question

simplify (p_2) (p+1) (p_4)​

Answer 1

Answer:

Comparing (p-2) , ( p+1) , (p-4) with (x+a) , ( x+b) , (x+c)

Then , x=p ; a= —2; b = 1 ; c = —4

(x+a)(x+b)(x+c)

= x³ + ( a+ b+ c) x² + ( ab+bc+ca)x + ABC

= p³ + { —2+1+(-4)} p² +{(-2)+1} + { (1)(-4)(-4)(-2) p } + { (-2)(1)(-4)}

= p³ + (—5)p² + { -2+(-4)+8} p + 8

= p³- 5p² + 2p + 8

Step-by-step explanation:

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