simplify (p-2)(p+1)(p-4)
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Answered by
1
Answer:
p³-5p²+2p+8
Step-by-step explanation:
First distribute to get ((p-2)(p+1))(p-4)
Now, distribute into (p-4) to get ((p-2)(p+1))(p)+((p-2)(p+1))(-4)
Distribute into each of these to get p³-p²-2p-4p²+4p+8
Combine like terms to get p³-5p²+2p+8
Answered by
2
Step-by-step explanation:
Comparing (p – 2) (p + 1) (p – 4) with (x + a) (x + b) (x + c) we have x = p ; a = -2; b = 1 ; c = -4. (x + a) (x + b) (x + c) = x3 + (a + b + c) x2 + (ab + be + ca) x + abc = p3 + (-2 + 1 + (-4))p2 + ((-2) (1) + (1) (-4) (-4) (-2)p + (-2) (1) (-4) = p3 + (-5 )p2 + (-2 + (-4) + 8)p + 8 = p3 – 5p2 + 2p + 8Read more on Sarthaks.com - https://www.sarthaks.com/982154/simplify-p-2-p-1-p-4
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