Math, asked by Divya2675, 6 months ago

simplify (p/q)^k * (q/r)^k+2 * (r/p)^k-1 ,for k=2

Answers

Answered by Anonymous
3

Solution:-

 \bf \:(  \frac{p}{q} ) {}^{k}  \times ( \frac{q}{r} ) {}^{k + 2}  \times ( \frac{r}{p} ) {}^{k - 1}

In wich value of k = 2

So put the value of k on given equation

\bf \:(  \frac{p}{q} ) {}^{2}  \times ( \frac{q}{r} ) {}^{2 + 2}  \times ( \frac{r}{p} ) {}^{2 - 1}

\bf \:(  \frac{p}{q} ) {}^{2}  \times ( \frac{q}{r} ) {}^{4}  \times ( \frac{r}{p} ) {}^{1}

\bf \:   \frac{p {}^{2} }{q {}^{2} } \times  \frac{q {}^{4} }{r {}^{4} } \times  \frac{r}{p}

Now we write

 \bf \:  \frac{p \times p \times q \times q \times q \times q \times r}{q \times q \times r \times r \times r \times r \times p}

\bf \:  \frac{ \not \: p \times p \times \not \:  q \times \not q \times q \times q \times \not r}{ \not \: q \times  \not \: q \times \not r \times r \times r \times r \times \not p}

 \to \bf \:  \frac{pq {}^{2} }{ {r}^{3} }

 \boxed{ \green{  \large \: \bf \: answer =  \bf \:  \frac{pq {}^{2} }{ {r}^{3} } }}

Answered by SHUBHRADEEPBAGH29
0

Answer.

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