Question

Simplify
(P² - Pq) -( pq -q²) and find
the value when P = 1 and qu= 2​

Answer 1

Answer:

Step-by-step explanation:

(P -12)x² +2( P -12) x + 2 =0 have two real and equal roots so,

D = b² -4ac =0

here,

b = 2( P -12)

a = (P -12)

c = 2

now,

D = {2(P -12)}² -4.2(P -12) =0

4{ (P -12)² -2( P -12) } =0

(P -12)² -2(P -12)=0

(P -12){ P -12 -2} = 0

(P -12)( P -14) =0

P = 12, 14

hence value of P = 12, 14

Answer 2

(P² - pq) -( pq -q²)

= p2-pq-pq+q²

= p²-2pq+q²

= (p-q)²

= (1-2)²

= (-1)²

= 1 Ans.