simplify part 6 pls help.
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hope this helps....
if correct.....mark as brainlist plzz.....
if correct.....mark as brainlist plzz.....
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taruno:
thanks a lot
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Given Equation can be written as:
![\frac{1}{(2 - \sqrt{3})^3 } + \frac{1}{(2 + \sqrt{3})^3 } \frac{1}{(2 - \sqrt{3})^3 } + \frac{1}{(2 + \sqrt{3})^3 }](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B%282+-++%5Csqrt%7B3%7D%29%5E3+%7D+%2B++%5Cfrac%7B1%7D%7B%282+%2B++%5Csqrt%7B3%7D%29%5E3+%7D+)
![\frac{(2 + \sqrt{3})^3 + (2 - \sqrt{3})^3 }{(2 + \sqrt{3})^3(2 - \sqrt{3})^3 } \frac{(2 + \sqrt{3})^3 + (2 - \sqrt{3})^3 }{(2 + \sqrt{3})^3(2 - \sqrt{3})^3 }](https://tex.z-dn.net/?f=+%5Cfrac%7B%282+%2B++%5Csqrt%7B3%7D%29%5E3+%2B+%282+-++%5Csqrt%7B3%7D%29%5E3+%7D%7B%282+%2B++%5Csqrt%7B3%7D%29%5E3%282+-++%5Csqrt%7B3%7D%29%5E3++%7D+)
We know that (a+b)^3 = a^3+b^3+3a^2b + 3ab^2, (a-b)^3 = a^3-b^3 -3a^2b+3ab^2.
![\frac{2^3+(\sqrt{3} )^3+3*2^2 \sqrt{3} + 3*2( \sqrt{3})^2 + 2^3 - 3 * 2^2 * \sqrt{3} + 3 * 2( \sqrt{3})^2 - ( \sqrt{3})^3 }{(2 + \sqrt{3})^3 (2 - \sqrt{3} )^3 } \frac{2^3+(\sqrt{3} )^3+3*2^2 \sqrt{3} + 3*2( \sqrt{3})^2 + 2^3 - 3 * 2^2 * \sqrt{3} + 3 * 2( \sqrt{3})^2 - ( \sqrt{3})^3 }{(2 + \sqrt{3})^3 (2 - \sqrt{3} )^3 }](https://tex.z-dn.net/?f=+%5Cfrac%7B2%5E3%2B%28%5Csqrt%7B3%7D+%29%5E3%2B3%2A2%5E2+%5Csqrt%7B3%7D+%2B+3%2A2%28+%5Csqrt%7B3%7D%29%5E2+%2B+2%5E3+-+3+%2A+2%5E2+%2A++%5Csqrt%7B3%7D+%2B+3+%2A+2%28+%5Csqrt%7B3%7D%29%5E2+-+%28+%5Csqrt%7B3%7D%29%5E3++%7D%7B%282+%2B++%5Csqrt%7B3%7D%29%5E3+%282+-++%5Csqrt%7B3%7D+%29%5E3+%7D+)
![\frac{12 \sqrt{3} + 3 \sqrt{3}+ 8 + 18 + 8 + 18 - 15 \sqrt{3} }{676 - 675} \frac{12 \sqrt{3} + 3 \sqrt{3}+ 8 + 18 + 8 + 18 - 15 \sqrt{3} }{676 - 675}](https://tex.z-dn.net/?f=+%5Cfrac%7B12+%5Csqrt%7B3%7D+%2B+3+%5Csqrt%7B3%7D%2B+8+%2B+18+%2B+8+%2B+18+-+15+%5Csqrt%7B3%7D+++%7D%7B676+-+675%7D+)
![\frac{15 \sqrt{3} + 26 + 26 - 15 \sqrt{3} }{1} \frac{15 \sqrt{3} + 26 + 26 - 15 \sqrt{3} }{1}](https://tex.z-dn.net/?f=+%5Cfrac%7B15+%5Csqrt%7B3%7D+%2B+26+%2B+26+-+15+%5Csqrt%7B3%7D+%7D%7B1%7D+)
![\frac{52}{1} \frac{52}{1}](https://tex.z-dn.net/?f=+%5Cfrac%7B52%7D%7B1%7D+)
52.
Hope this helps!
We know that (a+b)^3 = a^3+b^3+3a^2b + 3ab^2, (a-b)^3 = a^3-b^3 -3a^2b+3ab^2.
52.
Hope this helps!
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