Question

simplify:please answers ​

Answer 1

Answer:

Hope you understand that problem

Answer 2

$[(\frac{1}{2})^{2} +(\frac{4}{5})^{-2} ] /(2)^{-5}$

First we'll apply the negative power rule which is ⇒ $a^{-m} =\frac{1}{a^{m} }$

$[(\frac{1}{2})^{2} +(\frac{5}{4})^{2} ]/(\frac{1}{2} )^{5}$

Now we will substitute and give the whole value to all the numbers.

$[(\frac{1}{2*2})+ (\frac{5*5}{4*4} )]/(\frac{1*1*1*1*1}{2*2*2*2*2} )$

$[(\frac{1}{4})+(\frac{25}{16})]/\frac{1}{32}$

According to BODMAS we will do brackets first.

LCM = 16

$[\frac{1*4}{4*4} +\frac{25}{16}]/\frac{1}{32}$

$[\frac{4}{16}+\frac{25}{16} ]/\frac{1}{32}$

$\frac{29}{16} /\frac{1}{32}$

$\frac{29}{16}*\frac{32}{1}$

$\frac{29}{16/16} *32/16$

$29*2$

$58$

∴ $[(\frac{1}{2})^{2} +(\frac{4}{5})^{-2} ] /(2)^{-5}=58$