Math, asked by Anonymous, 1 year ago

simplify please give me correct answer

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Answered by aman190k
1
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by \: rationalising :  \\  \\   = \frac{3 \sqrt{2} - 2 \sqrt{3}  }{3 \sqrt{2} + 2 \sqrt{3}  }  +  \frac{ \sqrt{12} }{ \sqrt{3}  -  \sqrt{2} }  \\  \\  = \frac{3 \sqrt{2} - 2 \sqrt{3}  }{3 \sqrt{2} + 2 \sqrt{3}  } \times \frac{3 \sqrt{2} - 2 \sqrt{3}  }{3 \sqrt{2}  -  2 \sqrt{3}  }  +  \frac{ 2\sqrt{3} }{ \sqrt{3}  -  \sqrt{2} } \times    \frac{ \sqrt{3}  +  \sqrt{2} }{ \sqrt{3}   + \sqrt{2} } \\  \\  = \frac{ {(3 \sqrt{2} - 2 \sqrt{3}  )}^{2} }{ {(3 \sqrt{2} )}^{2} -  {(2 \sqrt{3} )}^{2}  }  +  \frac{2 \sqrt{3} \times ( \sqrt{3} +  \sqrt{2} )  }{ {( \sqrt{3} )}^{2}  -  {( \sqrt{2} )}^{2} }  \\  \\  =  \frac{18 + 12 - 12 \sqrt{6} }{18 - 12}  +  \frac{6 + 2 \sqrt{6} }{3 - 2}  \\  \\  =  \frac{6 \times (3 + 2 - 2 \sqrt{6}) }{6}  +  \frac{6 + 2 \sqrt{6} }{1}  \\  \\ = \frac{ (3 + 2 - 2 \sqrt{6}) }{1}  +  \frac{6 + 2 \sqrt{6} }{1} \\  \\   = 5 - 2 \sqrt{6}  + 6 + 2 \sqrt{6}  \\  \\  = 11
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Anonymous: okk
Anonymous: ok
Answered by Anonymous
0
Heya,
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See the above pic....for your answer !
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Hope it helps....and sorry if there are any mistake in my answer ☺
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