Question

simplify
please give me the answer ​

Answer 1

Given,

⇒a2−a−12a2+5a+6×a2−4a−4

=a2−4a+3a−12a2+3a+2a+6×(a+2)(a−2)a−4

=a(a−4)+3(a−3)a(a+3)+2(a+3)×(a+2)(a−2)(a−4)

=(a−4)(a+3)(a+3)(a+2)×(a+2)(a−2)(a−4)

=a−21.

Answer 2

Answer:

$\frac{1}{a-2}$

Step-by-step explanation:

CANCEL a^2+5a+6/a^2-a-12: a+2/a-4

= a+2/a-4 x a-4/a^2-4

CROSS-CANCEL COMMON FACTOR: a-4

= a+2/a^2-4

FACTOR a^2-4: (a+2)(a-2)

= a+2/(a-2)(a-2)

CANCEL THE COMMON FACTOR: a+2

= 1/a-2

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