simplify
please give me the answer
Attachments:

Answers
Answered by
0
Given,
⇒a2−a−12a2+5a+6×a2−4a−4
=a2−4a+3a−12a2+3a+2a+6×(a+2)(a−2)a−4
=a(a−4)+3(a−3)a(a+3)+2(a+3)×(a+2)(a−2)(a−4)
=(a−4)(a+3)(a+3)(a+2)×(a+2)(a−2)(a−4)
=a−21.
Answered by
0
Answer:
Step-by-step explanation:
CANCEL a^2+5a+6/a^2-a-12: a+2/a-4
= a+2/a-4 x a-4/a^2-4
CROSS-CANCEL COMMON FACTOR: a-4
= a+2/a^2-4
FACTOR a^2-4: (a+2)(a-2)
= a+2/(a-2)(a-2)
CANCEL THE COMMON FACTOR: a+2
= 1/a-2
-
PLS. MARK ME AS THE BRAINLIEST. HOPE THIS HELPS.
Similar questions