Question

simplify please I need this answer help.me please ​

Answer 1

Answer:

$(x^{a} )^{b-c} *(x^{b} )^{c-a} *(x^{c})^{a-b}$

=$x^{ab-ac} *x^{bc-ba} *x^{ac-ab}$

=$x^{ab-ac+bc-ba+ac-cb}$

=$x^{0}$

=1