Math, asked by pappikandari, 1 year ago

simplify please it is urgent ​

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Answered by Anonymous
7

Solution :-

Given

 \dfrac{7}{20} + \dfrac{17}{-45} + \dfrac{-11}{-13} + \dfrac{-8}{15}

 = \dfrac{7}{20} + \dfrac{-17}{45} + \dfrac{11}{13} + \dfrac{-8}{15}

Now we have to find out the

LCM of 20 , 45 , 13 , 15

20 = 2² × 5

45 = 3² × 5

13 = 13 × 1

15 = 3 × 5

So LCM of 20 , 45 , 13 , 15

= 2² × 3² × 13 × 5

= 4 × 9 × 13 × 5

= 2340

Now as

20 × 117 = 2340

Then  \dfrac{7}{20} = \dfrac{819}{2340}

45 × 52 = 2340

Then  \dfrac{-17}{45} = \dfrac{-884}{2340}

13 × 180 = 2340

Then  \dfrac{11}{13} = \dfrac{1980}{2340}

15 × 156 = 2340

Then  \dfrac{-8}{15} = \dfrac{-1248}{2340}

So now sum

 = \dfrac{819}{2340} + \dfrac{-884}{2340} + \dfrac{1980}{2340} + \dfrac{-1248}{2340}

 = \dfrac{819 - 884}{2340} + \dfrac{1980 - 1248}{2340}

 = \dfrac{-65}{2340} + \dfrac{732}{2340}

 = \dfrac{667}{2340}

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