simplify:
pls solve this question right now
n thnx in advance
Answers
[tex]\mathfrak{\huge{Answer:-}} \\ \bold{\frac{2 + \sqrt{3} }{2 - \sqrt{3} } + \frac{2 - \sqrt{3} }{2 + \sqrt{3} } + \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } } \\ = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } + \frac{2 - \sqrt{3} }{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } + \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1 } \\ = \frac{(2 + \sqrt{3} )(2 + \sqrt{3}) }{(2 - \sqrt{3} )(2 + \sqrt{3}) } + \frac{(2 - \sqrt{3} )(2 - \sqrt{3}) }{(2 + \sqrt{3} )(2 - \sqrt{3}) } + \frac{( \sqrt{3} - 1)( \sqrt{3} - 1) }{( \sqrt{3} + 1)( \sqrt{3} - 1)} \\ = \frac{ {(2 + \sqrt{3} )}^{2} }{ {(2)}^{2} - {( \sqrt{3} )}^{2} } + \frac{ {(2 - \sqrt{3}) }^{2} }{ {(2)}^{2} - {( \sqrt{3}) }^{2} } + \frac{ {( \sqrt{3} - 1) }^{2} }{ {( \sqrt{3}) }^{2} - {(1)}^{2} } \\ = \frac{4 + 3 + 4 \sqrt{3} }{4 - 3} + \frac{4 + 3 - 4 \sqrt{3} }{4 - 3} + \frac{3 + 1 - 2 \sqrt{3} }{3 - 1} \\ = \frac{7 + 4 \sqrt{3} }{1} + \frac{7 - 4 \sqrt{3} }{1} + \frac{4 - 2 \sqrt{3} }{2} \\ = 7 + 4 \sqrt{3} + 7 - 4 \sqrt{3} + \frac{2(2 - \sqrt{3}) }{2} \\ = 7 + 4 \sqrt{3} + 7 - 4 \sqrt{3} + 2 - \sqrt{3} \\ = 7 + 7 + 2 - \sqrt{3} + 4 \sqrt{3} - 4 \sqrt{3} \\ = 16 - \sqrt{3} \\ \boxed{\boxed{\large{\bold{ \frac{2 + \sqrt{3} }{2 - \sqrt{3} } + \frac{2 - \sqrt{3} }{2 + \sqrt{3} } + \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1 } = 16 - \sqrt{3} }}}}[/tex]
Thomspon was a great scientists who proposed that atoms are electrically neutral and there is a positively charged sphere where electrons are embedded in it......
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Army could you remember me I am ayontica