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Qᴜᴇsᴛɪᴏɴ:-
1/[1 + (x)^b-a + (x)^c-a] + 1/[1 + (x)^a-b + (x)^c-b] + 1/[1 + (x)^a-c + (x)^b-c]
Aɴsᴡᴇʀ:-
First solving 1/[1 + (x)^b-a + (x)^c-a] :-
We know p^(m-n) = (p^m)/(p^n)
p^m * p^n = p^(m+n)
1/[1 + (x)^b-a + (x)^c-a]
=> 1/[1 + x^b/x^a + x^c/x^a]
=> 1/[ (x^a + x^b + x^c)/x^a]
=> x^a/(x^a + x^b + x^c)
Solving 1/[1 + (x)^a-b + (x)^c-b] :-
1/[1 + (x)^a-b + (x)^c-b]
=> 1/[( + x^a/x^b + x^c/x^b]
=> 1/[(x^b + x^a + x^c)/x ^b]
=> x^b/(x^b + x^a + x^c)
Solving 1/[1 + (x)^a-c + (x)^b-c] :-
1/[1 + (x)^a-c + (x)^b-c]
=> 1/[1 + x^a/x^c + x^b/x^c]
=> 1/[(x^c + x^a + x^b)/x^c]
=> x^c/(x^c + x^a + x^b)
Adding them :-
x^a/(x^a + x^b + x^c) + x^b/(x^b + x^a + x^c) + x^c/(x^c + x^a + x^b)
=> x^a/(x^a + x^b + x^c) + x^b/(x^a + x^b + x^c) + x^c/(x^a + x^b + x^c )
=> (x^a + x^b + x^c)/(x^a + x^b + x^c)
=> 1
Ans. = 1
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