Question

Simplify
Q1. (√3-√3)^2
Find the value of a and b
√3+1/√3-1=a+b√3

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hello Friend}}}$

$\frac{ \sqrt{3} + 1}{ \sqrt{3} - 1} \\ = \frac{ \sqrt{3} + 1 }{ \sqrt{3} - 1} \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1} \\ = \frac{3 - \sqrt{3} + \sqrt{3} - 1}{( \sqrt{3}) {}^{2} - 1 {}^{2} } \\ = \frac{2}{3 - 1} \\ = 1 \\ = a + b \sqrt{3} \\ on \: compaing \\ a = 1 \: \: and \: b = 0$


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Answer 2

Here is your answer
$= \frac{ \sqrt{3} + 1 }{ \sqrt{3} - 1} \times \frac{ \sqrt{3} + 1 }{ \sqrt{3} + 1} \\ = \frac{3 + \sqrt{3} + \sqrt{3} + 1 }{3 - 1} \\ = \frac{4 + 2 \sqrt{3} }{2} \\ = \frac{4}{2} + \frac{2 \sqrt{3} }{2} \\ = 2 + \sqrt{3} \\ = a + b \sqrt{3} \\ a = 2 \\ b = 1$
Hope it helps