Question

Simplify (R²-S²)³+(S²-T²)³+(T²-R²)³

Answer 1

Answer:

Step-by-step explanation:

Method 1: substitute  u=r2+x2  

Method 2: substitute $x=rtanθ$  and simplify the denominator using the identity $1+tan2θ=sec2θ$ . You will get   $1+tan2θ=sec2θ$

$1+tan2θ=sec2θ$

Use a right angle triangle to express  $sinθ$ in terms of  x .

To make sure your answer is correct differentiate it and see if you get back the original function in the integral.

hope it helps

:)

Answer 2

ANSWER ::

Let

a = (R²-S²), b = (S²-T²), c = (T²-R²)

Then

a+b+c = 0

We know that if a+b+c = 0 then a³ + b³ + c³ = 3abc

Therefore

(R²-S²)³+(S²-T²)³+(T²-R²)³

= 3(R²-S²)(S²-T²)(T²-R²)

Please Mark it Brainliest