Question

simplify rationalizing the denominator 7+3√5 /7-3√5​

Answer 1

Answer:

7−3

5

7+3

5

Multiplying both numerator and denominator with numerator

\frac{(7+3 \sqrt{5})^{2}}{(7-3 \sqrt{5})*(7+3 \sqrt{5})}

(7−3

5

)∗(7+3

5

)

(7+3

5

)

2

\frac{49+45+42 \sqrt{5} }{49-45}

49−45

49+45+42

5

\frac{94+ 42 \sqrt{5} }{4}

4

94+42

5

\frac{47+21 \sqrt{5} }{2}

2

47+21

5