Math, asked by raayalelastics6099, 8 months ago

Simplify. Rewrite the expression in the form x^nx n x, start superscript, n, end superscript. \dfrac{x^{5}}{x^2}= x 2 x 5 ​

Answers

Answered by paulmrinal01
10

Answer:

Example 1: Simplifying ~\dfrac{10x^3}{2x^2-18x}

2x

2

−18x

10x

3

space, start fraction, 10, x, cubed, divided by, 2, x, squared, minus, 18, x, end fraction

Step 1: Factor the numerator and denominator

Here it is important to notice that while the numerator is a monomial, we can factor this as well.

\dfrac{10x^3}{2x^2-18x}=\dfrac{ 2\cdot 5\cdot x\cdot x^2}{ 2\cdot x\cdot (x-9)}

2x

2

−18x

10x

3

=

2⋅x⋅(x−9)

2⋅5⋅x⋅x

2

start fraction, 10, x, cubed, divided by, 2, x, squared, minus, 18, x, end fraction, equals, start fraction, 2, dot, 5, dot, x, dot, x, squared, divided by, 2, dot, x, dot, left parenthesis, x, minus, 9, right parenthesis, end fraction

Step 2: List restricted values

From the factored form, we see that {x\neq0}x

=0x, does not equal, 0 and {x\neq9}x

=9x, does not equal, 9.

Step 3: Cancel common factors

\begin{aligned}\dfrac{ \tealD 2\cdot 5\cdot \purpleC{x}\cdot x^2}{ \tealD 2\cdot \purpleC{x}\cdot (x-9)}&=\dfrac{ \tealD{\cancel{ 2}}\cdot 5\cdot \purpleC{\cancel{x}}\cdot x^2}{ \tealD{\cancel{ 2}}\cdot \purpleC{\cancel{x}}\cdot (x-9)}\\ \\ &=\dfrac{5x^2}{x-9} \end{aligned}

2⋅x⋅(x−9)

2⋅5⋅x⋅x

2

=

2

x

⋅(x−9)

2

⋅5⋅

x

⋅x

2

=

x−9

5x

2

Answered by guddikumari77507
5

Answer:

3

is answer

you question the answer

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