Question

simplify root 128 simplify root 128 + root 50 ​

Answer 1

Answer:

$\sqrt{128 } = \sqrt{ {8 }^{2} + {8}^{2} } = \sqrt{2} \times 8 \\ \sqrt{50} = \sqrt{2} \times 5 \\ \sqrt{128 } + \sqrt{50} = (8 \sqrt{2} + 5 \sqrt{2} )$