Question

Simplify root 27 + 3root 12 with method​

Answer 1

Answer:

$= > \sqrt{27} + 3 \sqrt{12} \\ \\ = > \sqrt{9 \times 3} + 3 \sqrt{4 \times 3} \\ \\ = > 3 \sqrt{3} + 6 \sqrt{3} \\ \\ \\ = > \sqrt{3} (3 + 6) \\ \\ \\ = > 9 \sqrt{3}$

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Answer 2

Answer:

$\sqrt{27} + 3 \sqrt{12} \\ 3\sqrt{3} + 6 \sqrt{3} \\ 3 \sqrt{3} (1 + 2) \\ 3 \sqrt{3} \times 3 \\ 9 \sqrt{3}$

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