Question

simplify root 32+root 48 divded by root 8+root 12

Answer 1

ye lo bas thik he ap ka answer

Answer 2

Hi friend, Harish here.

Here is your answer;

To  find,

$\frac{ \sqrt{32}+ \sqrt{48} }{ \sqrt{8} + \sqrt{12} }$

Solution,

Take √4 as common in the numerator. 

Then, 

$\sqrt{32}+ \sqrt{48} = \sqrt{4} ( \sqrt{8}+ \sqrt{12})$

Now, let us divide.

Then,

$\frac{ \sqrt{32}+ \sqrt{48} }{ \sqrt{8} + \sqrt{12} } = \frac{\sqrt{4} ( \sqrt{8}+ \sqrt{12})}{( \sqrt{8}+ \sqrt{12})}$

Now, we can cancel. √8 + √12.

Then we get,

$\frac{\sqrt{4} ( \sqrt{8}+ \sqrt{12})}{( \sqrt{8}+ \sqrt{12})} = \sqrt{4} = 2.$

Therefore 2 is the answer.
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Hope my answer is helpful to you.