Question

simplify (root11-root7)(root11+root7)​

Answer 1

Answer:

use formula of (a+b)(a-b)

=(a^2-b^2)

here a =√11=>a^2=11

and b=√7=>b^2=7

so (a^2-b^2)=11-7=4 answer

Answer 2

Answer;

(root11-root7) (root 11+root 7)

by using the formula of (a square-b square)

which gives (a+ b)(a-b)

by doing this sum

we can reverse the formula

we can apply a square-b square

root 11 square- root 7 square

11-7

4

so the answer is 4

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