Question

Simplify root6/root3+root2

Answer 1

$\frac{ \sqrt{6} }{ \sqrt{3} } + \sqrt{2} \\ = > \frac{ \sqrt{3} \times \sqrt{2} }{ \sqrt{3} } + \sqrt{2} \\ = > \sqrt{2} + \sqrt{2} \\ = > 2 \sqrt{2}$

i hope that helps you

Answer 2

Answer:

$\frac{ \sqrt{6} }{ \sqrt{3} + \sqrt{2} } \\ \\ \frac{ \sqrt{6} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{6} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ \\ \frac{ \sqrt{6}( \sqrt{3} - \sqrt{2}) }{( \sqrt{3}) {}^{2} - ( \sqrt{2} ) {}^{2} } \\ \\ \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 - 2} \\ \\ =3 \sqrt{2} + 2 \sqrt{3}$

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