Math, asked by deepalisj14, 1 year ago

Simplify (sec^2A+tan^2A)^2-4sec^2A×tan^2A

Answers

Answered by vm983855
3
=(sec^2A+tan^2A)^2-4sec^2A×tan^2A

=( 1+tan^2A+tan^2A )^2-4(1+tan^2A)tan^2A

= (1+2tan^2A)^2-4 tan^2A-4tan^4A

=1+4tan^4A+4tan^2A-4tan^2A-4tan^4A

= 1+0+0

1. ans.

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Answered by mrsonu962
0
Here is ur ans. ....
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