Math, asked by sath1093, 7 months ago

Simplify: sec2x(1-sin2x)+secB(sinB/tanB)

Answers

Answered by classicpoint123

1

Step-by-step explanation:

From trig identities, sin2x+cos2x=1

∴1−sin2x=cos2x

∴sec2x(1−sin2x)=sec2x⋅cos2x

=1cos2x⋅cos2x

=1

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