simplify secA(1-sinA)(secA+tanA)
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Answered by
1
Step-by-step explanation:
Given : secA(1−sinA)(secA+tanA)
cosA1(1−sinA)(cosA1+cosAsinA)...................(∵secA=cosA1)
(cosA1−sinA)(cosA1+sinA)
cos2A1−sin2A
As, 1−sin2A=cos2A
cos2Acos2A =1
Answered by
2
Step-by-step explanation:
= secA(1-sinA)(secA+tanA)
= (1/cosA)(1-sinA)(1/cosA+sinA/cosA)
= (1/cos²A)(1-sinA)(1+sinA)
= (1/cos²A)(1-sin²A)
= (1/cos²A)(cos²A)
= 1
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