SIMPLIFY (SECA(1-SINA)SECA+TANA)
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Answered by
150
(secA)(1-sinA)(secA + tanA)
= (1/cosA)(1-sinA)(1/cosA + sinA/cosA)
= (1-sinA/cosA)(1+sinA/cosA)
= 1-sin²A/cos²A
= cos²A/cos²A
= 1
Hope that helps !!
= (1/cosA)(1-sinA)(1/cosA + sinA/cosA)
= (1-sinA/cosA)(1+sinA/cosA)
= 1-sin²A/cos²A
= cos²A/cos²A
= 1
Hope that helps !!
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Answered by
60
secA (1-sinA) (secA+tanA)
= (1/cosA) (1-sinA) (1/cosA+sinA/cosA)
= (1/cosA) (1-sinA) (1+sinA) /cosA
= (1/cos²A) (1-sin²A)
= (1/cos²A) (cos²A)
= 1
= (1/cosA) (1-sinA) (1/cosA+sinA/cosA)
= (1/cosA) (1-sinA) (1+sinA) /cosA
= (1/cos²A) (1-sin²A)
= (1/cos²A) (cos²A)
= 1
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