Math, asked by a3427741, 1 day ago

simplify Sin (2A+3B) Cos (2A-3B)+Cos(2A+3B)Sin(2A-3B)

Answers

Answered by rs2302667
1

Answer:

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Answered by amitnrw
0

Given :   Sin (2A+3B) Cos (2A-3B)+Cos(2A+3B)Sin(2A-3B)

To Find : Simplify

Solution:

Sin (2A+3B) Cos (2A-3B)+Cos(2A+3B)Sin(2A-3B)

Sin x Cosy + Cosx Siny = Sin(x + y)

x = 2A + 3B

y = 2A - 3B

=> Sin (2A+3B) Cos (2A-3B)+Cos(2A+3B)Sin(2A-3B)   = Sin ( 2A + 3B + 2A - 3B)

=> Sin (2A+3B) Cos (2A-3B)+Cos(2A+3B)Sin(2A-3B)   = Sin (4 A)

Sin (2A+3B) Cos (2A-3B)+Cos(2A+3B)Sin(2A-3B)   = Sin (4 A)  

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If 2 sin x = sin y and 2 cos x = 3 cos y then find the value of tan (x + y)

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