Simplify sin cube theta + cos cube theta by sin theta + cos theta + sin theta into cos theta
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Sin^3 theta + cos ^3 theta÷sintheta + cos theta +sin theta cos theta
Answer:
Sin^3 theta + cos ^3÷ sin theta + cos theta + ( sin theta × cos theta )( sin theta + cos theta) ÷ sin theta + cos theta
Sin^3theta + cos^3theta + sin^2theta×cos theta + sin theta × cos^2 ÷ sin theta + cos theta =
(Sin theta + cos theta)^3 ÷sin theta + cos theta = (sin theta + cos theta )^2
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