Math, asked by triggerAVS8417, 3 months ago

Simplify: [sin(_Q)tan(90+Q)sin(180+Q)sec(270+Q)]/[sin(360_Q)cos(270_Q)cosec(180_Q)cot(360_Q)]

Answers

Answered by riteshyadav9969

0

Step-by-step explanation:

=[sin(_Q)tan(90+Q)sin(180+Q)sec(270+Q)]/[sin(360_Q)cos(270_Q)cosec(180_Q)cot(360_Q)

solving using unit circle

=(-sinQ)(-cotQ)(-sinQ)(cosecQ) /

(-sinQ)(-sinQ)(cosecQ)(-cotQ)

=1

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