Math, asked by shivamsingh99, 1 year ago

simplify : sin theta - 2sin cube theta / 2 cos cube theta - cos theta

Answers

Answered by shanjaysundar2000
1

(sin∅-2sin³∅)/(2cos³∅-cos∅)

=sin∅(1-2sin²∅)/cos∅(2cos²∅-1)

=sin[1-2+2cos²∅]/cos∅(2cos²∅-1)

=sin∅(2cos²∅-1)/cos∅(2cos²∅-1)

=sin∅/cos∅

=tan∅

Similar questions